ajax无刷新上传图片实例

【 tulaoshi.com - Web开发 】

将index.html和upload.php文件保存到apache工作目录，例子使用安装目录D:/Program Files/Apache Software Foundation/Apache2.2/htdocs/

AJAX 客户端页面代码： index.html

html 
body 
h1Ajax file upload sample/h1br/input id="uplaod" name="btn_send" type="button" value="上传测试"/ 
div id=result/div 
PRE class=js name="code"SCRIPT LANGUAGE=JavaScript   
// 上传函数   
function btn_send.onclick() {   
 data = "" 
 spliter = "-------7d8d733180846" 
 datadata = data + spliter + ""  
 datadata = data + "Content-Disposition: form-data; name="photofile"; filename="C:a.txt""  
 // datadata = data + "Content-Type: image/pjpeg" + vbCrLf  
 datadata = data + "Content-Type: text/plain" + "" + ""  
 text = "My name is Wilson Lin." 
 postLength = text.length + data.length + 2 + spliter.length + 4  
 package = data + text + "" + spliter + "--"  
 
 alert(package)  
 // 把XML文档发送到Web服务器   
 var xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");   
 xmlhttp.open("POST","./upload.php",false);   
 xmlhttp.setRequestHeader("Content-Type", "multipart/form-data; boundary=-----7d8d733180846");  
 xmlhttp.setRequestHeader("Content-Length", postLength);  
 xmlhttp.send(package);   
 // 显示服务器返回的信息   
 result.innerHTML=xmlhttp.ResponseText;  
}   
/SCRIPT   
/PRE 
 /body 
/html

PHP服务器端代码： upload.php

？php 
// $_FILES['photofile']:是获得上传图片的数组  
// $uploadfile：存放地址  
$uploadfile = "D:/Program Files/Apache Software Foundation/Apache2.2/htdocs/".$_FILES['photofile']['name'];  
copy( $_FILES['photofile']['tmp_name'], $uploadfile );  
echo "URL: a href='http://localhost/".$_FILES['photofile']['name']."' target='_blank'".$_FILES['photofile']['name']."/abr/";  
？ 
Upload successed!