Create function fun_getPY
(
@str nvarchar(4000)
)
returns nvarchar(4000)
as
begin
declare @word nchar(1),@PY nvarchar(4000)
set @PY=''
while len(@str)0
begin
set @word=left(@str,1)
--如果非汉字字符,返回原字符
set @PY=@PY+(case when unicode(@word) between 19968 and 19968+20901
then (
select top 1 PY
from
(
select 'A' as PY,N'驁' as word
union all select 'B',N'簿...[ 查看全文 ]