Create function fun_getPY ( @str nvarchar(4000) ) returns nvarchar(4000) as begin declare @word nchar(1),@PY nvarchar(4000) set @PY='' while len(@str)0 begin set @word=left(@str,1) --如果非汉字字符,返回原字符 set @PY=@PY+(case when unicode(@word) between 19968 and 19968+20901 then ( select top 1 P...[ 查看全文 ]